Solutions to Henderson-Hasselbalch problems 4, 5, 6

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Three example problems of buffer calculations with a base and its salt

As a reminder, here is the Henderson-Hasselbalch Equation:

The Ka for anisic acid is 3.38 x 10¯5; the pKa equals 4.471.

Problem #4:

pH = 4.471 + log (1.00 / 1.00)

pH = 4.471

Problem #5:

pH = 4.471 + log (0.800 / 0.600)

pH = 4.471 + 0.125 = 4.596

Problem #6:

pH = 4.471 + log (0.300 / 0.700)

pH = 4.471 - 0.368 = 4.103

A Henderson- Hasselbalch calculator. Have fun!

Below the calculator is a list of acids and bases with their pKa values. Please note that pKb values are not given for bases. What is given is the pKa value for the conjugate acid to the base.

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