How to Calculate an Average Atomic Weight


To do these problems you need some information: the exact atomic weight for each naturally-occuring stable isotope and its percent abundance. These values can be looked up in a standard reference book such as the "Handbook of Chemistry and Physics."

This problem can also be reversed. Study the tutorial below and then look at the problems done in the reverse direction.

Example #1: Carbon

mass numberexact weightpercent abundance
1212.00000098.90
1313.0033551.10

To calculate the average atomic weight, each exact atomic weight is multiplied by its percent abundance (expressed as a decimal). Then, add the results together and round off to an appropriate number of significant figures.

This is the solution for carbon:

(12.000000) (0.9890) + (13.003355) (0.0110) = 12.011


Example #2: Nitrogen

mass numberexact weightpercent abundance
1414.00307499.63
1515.0001080.37

This is the solution for nitrogen:

(14.003074) (0.9963) + (15.000108) (0.0037) = 14.007

Video: How to Calculate an Average Atomic Weight.


Example #3: Chlorine   Example #4: Silicon
mass numberexact weightpercent abundance   mass numberexact weightpercent abundance
3534.96885275.77   2827.97692792.23
3736.96590324.23   2928.9764954.67
     3029.9737703.10
The answer for chlorine: 35.453 The answer for silicon: 28.086

This type of calculation can be done in reverse, where the isotopic abundances can be calculated knowing the average atomic weight. Go to tutorial on reverse direction.

Example #5: In a sample of 400 lithium atoms, it is found that 30 atoms are lithium-6 (6.015 g/mol) and 370 atoms are lithium-7 (7.016 g/mol). Calculate the average atomic mass of lithium.

Solution:

1) Calculate the percent abundance for each isotope:

Li-6: 30/400 = 0.075
Li-7: 370/400 = 0.925

2) Calculate the average atomic weight:

x = (6.015) (0.075) + (7.016) (0.925)

x = 6.94 g/mol


Practice Problems

Calculate the average atomic weight for:

1) magnesium

mass numberexact weightpercent abundance
2423.98504278.99
2524.98583710.00
2625.98259311.01

2) molybdenum

mass numberexact weightpercent abundance
9291.90680814.84
9493.9050859.25
9594.90584015.92
9695.90467816.68
9796.9060209.55
9897.90540624.13
10099.9074779.63

3) tin (this one is optional!! Suggestion: set it up as a spreadsheet, take it into class and impress your teacher.)

mass numberexact weightpercent abundance
112111.9048260.97
114113.9027840.65
115114.9033480.36
116115.90174714.53
117116.9029567.68
118117.90160924.22
119118.9033108.58
120119.90220032.59
122121.9034404.63
124123.9052745.79

The answers? Look on a periodic table!! Remember that the above is the method by which the average atomic weight for the element is computed. No one single atom of the element has the given atomic weight because the atomic weight of the element is an average, specifically called a "weighted" average.

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