Dichromate half-reaction answer

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Here is the half-reaction in acid solution:

Cr₂O₇²¯ ---> Cr³⁺

Step One: Balance the atom being reduced/oxidized.

Cr₂O₇²¯ ---> 2Cr³⁺

Step Two: Balance the oxygens.

Cr₂O₇²¯ ---> 2Cr³⁺ + 7H₂O

Step Three: Balance the hydrogens.

14H⁺ + Cr₂O₇²¯ ---> 2Cr³⁺ + 7H₂O

Step Four: Balance the total charge.

6e¯ + 14H⁺ + Cr₂O₇²¯ ---> 2Cr³⁺ + 7H₂O

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