Dichromate half-reaction answer

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Here is the half-reaction in acid solution:

Cr2O72¯ ---> Cr3+

Step One: Balance the atom being reduced/oxidized.

Cr2O72¯ ---> 2Cr3+

Step Two: Balance the oxygens.

Cr2O72¯ ---> 2Cr3+ + 7H2O

Step Three: Balance the hydrogens.

14H+ + Cr2O72¯ ---> 2Cr3+ + 7H2O

Step Four: Balance the total charge.

6e¯ + 14H+ + Cr2O72¯ ---> 2Cr3+ + 7H2O

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